Sequential (118) Parallel in/out line

https://chihaukam.blogspot.com/2026/01/bradley-you-tell-chris.html?m=1

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Ref: https://chihaukam.blogspot.com/2024/04/see_27.html?m=1 .

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John : Take a look.  https://chihaukam.blogspot.com/2024/04/see_27.html?m=1 . This article said, after System Circuit "put" the Register_A on the RJ45 Circuit,  System Circuit already lost the control of Register_A. 

Me: Therefore,  Parallel output line must be based on RJ45 Circuit. 

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John : Yes, Mov buffer_zone, value. It represents.

Object[Buffer_zone] <--- At the stage of mask interrupt only.

Value of input[0100001001111111] <-- Link to the clock line of RJ45 already.

Me: "Value of input" is linked to the clock line of RJ45,  

John : Ok.

Me: Yet, "The Object" is only at the stage of mask interrupt. 

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John: Originally,  "Value of input" shift right. Yes,  If  "value of input" shift left, the Object can be changed.  However,  the Object is at the stage of Mask interrupt.  Therefore,  the object has no input.

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Me: Therefore, you can't change it from (int buffer_zone = value) into (int Spi_clock_line = value)

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John : Do you notice that parallel output line is the branch of the clock line of RJ45 ?

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Me: Yes,

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John: So,

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First,  hack the clock line of RJ45.  

Second,  generate a signal of 1001001 on the parallel output line. 

Third, the signal of 1001001 mean Object [ Spi_clock_line ]. 

Four, it become.

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For (int i = 0; i < 100; i++)

{

Sum = Sum + i;

if (i == 100)

{

Int Spi_clock_line = Sum;

<---- Originally,  it is that Int buffer_zone = Sum.

}

}

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Originally, 

Spi_clock_line [System clock line].

After hacking, 

Spi_clock_line [RJ45]